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nekit [7.7K]
3 years ago
13

I need help with this now

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0
The third one. Because
You might be interested in
For what value(s) of the constant b does the equation f(x)=3x^2+bx+27 have 1 x-intercept
lions [1.4K]

Step-by-step explanation:

An a quadratic equation,

{ax}^{2}  +  bx + c = 0

If the quadratic has one solution,

then

b {}^{2}  - 4ac = 0

So plug in 27 for c, and 3 for a

{b}^{2}  - 4(3)(27) = 0

{b}^{2}  - 324 = 0

{b}^{2}  = 324

b = 18

or

b =  - 18

So our answer is 18 or -18

7 0
2 years ago
96,240 is divisible by 2, 4, and 8. true or false?
VikaD [51]

Answer:

false

Step-by-step explanation:

96,240

a-9

2,3

8,9

4 0
3 years ago
Draw graphs of the following lines: The line through (-5, 2) having the slope of -3
Ivanshal [37]
What you want to do here is take this information and plug it into point-slope form. any time you're given a point and a slope, you generally want to plug it into this equation: y - y1 = m(x - x1).

in this equation, m is your slope and (x1, y1) is a given point. plug in your info--slope of -3 and (-5, 2).

y - 2 = -3(x + 5)

that is the equation of your line. however, if you want to graph it, this doesn't really make much sense to you. convert it to slope-intercept form, y = mx + b, by solving for y.

y - 2 = -3(x + 5) ... distribute -3
y - 2 = -3x - 15 ... add 2
y = -3x - 13 is your equation.

to graph this, and any other y = mx + b equation, you want to start with your y-intercept if it's present. your y intercept here is -13, which means the line you wasn't to graph crosses the y-axis at y = -13, or (0, -13). put a point there.

after you've plotted that point, you use your slope to graph more. remember that your slope is "rise over run"--you rise up/go down however many units, you run left/right however many units. if your slope is -3, you want to go down 3 units, then go to the right 1 unit. remember that whole numbers have a 1 beneath them as a fraction. -3/1 is your rise over 1.
6 0
3 years ago
Read 2 more answers
An online furniture store sells chairs for $150 each and tables for $400 each. Every day, the store can ship no more than 30 pie
ivolga24 [154]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you!

4 0
3 years ago
Values of an expression
REY [17]
Substitute a number for each variable

Ex.
2x x=5
(2)(5)
=10
6 0
3 years ago
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