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4 years ago

What percent of 25 is 14?

2 answers:

6 0

Part = 14
Total = 25
Percent = 56%

14 ÷ 25 = 0.56 × 100% = 56%.

14 is 56% of 25.

When the part and whole is given, divide the part by the whole to get the percentage.
When the part and corresponding percentage is given, divide the part by the corresponding percentage in decimal form to get the whole.
14/0.56 = 25
When the whole and percentage is given, multiply the whole by the percentage in decimal form to get the value of the part.
25 * 0.56 = 14

Xelga [282]4 years ago

6 0

Part=14
Total=25
Percentage=56%
14/25=0.56*100=56%

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Step-by-step explanation:

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3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

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3 years ago

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malfutka [58]

Answer:

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3 years ago

Can someone help with step by step

MrMuchimi

Answer:

See explanation

Step-by-step explanation:

$In\: \triangle ABC \:\&\: \triangle EDC\\\angle ABC \cong \angle EDC... (Right \: \angle s) \\\angle ACB \cong \angle ECD... (Vertical \: \angle s) \\\therefore \triangle ABC \sim \triangle EDC... (By\: AA\: Postulate) \\$

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3 years ago