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Ulleksa [173]
4 years ago
12

two steamers leave a port on a river at the same time traveling in opposite directions each is traveling 80 miles per hour how l

ong would it take for them to be 90 miles apart
Mathematics
1 answer:
GenaCL600 [577]4 years ago
4 0
<span>What you know: speed of the ships = 80 mph
Combined speed = 80+80 = 160 mph
Time = distance/combined speed -> time = 90/160 -> time = 0.56

</span>
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The ratio of red counters to blue counters is 1 : 3
jolli1 [7]

Answer:

Nov 20, 2016 · If we assume that initially Number of red counter is 1 Number of blue counter is 3 Now to make ratio reverse you need to add 8 more red counters so that ratio becomes 9:3=3:1

Step-by-step explanation:

6 0
3 years ago
How many pieces 3 and three fifths in. long can be cut from 28 metal rods each 15 in.​ long? Disregard waste.
Murrr4er [49]

Answer: 112 pieces


Step-by-step explanation:

1. Rewrite 3^{\frac{3}{5}} as a decimal. Divide the numerator and the denominator of the fractional part and add it to the integer part:

3+0.6=3.6in

2. You know that each metal rod is 15 inches long. Then, you must divide the lenght of each one by 3.6:

pieces=\frac{15in}{3.6in}4.16

3. The waste is 0.16, therefore, you obtain 4 pieces from a metal rod. The total pieces obtained from 28 metal rods are:

total=4pieces*28=112pieces

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3 years ago
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Multiply both sides by "x"

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6 0
3 years ago
Please help me as soon as possible
Alex777 [14]

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5 0
2 years ago
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The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
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