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Ulleksa [173]
3 years ago
12

two steamers leave a port on a river at the same time traveling in opposite directions each is traveling 80 miles per hour how l

ong would it take for them to be 90 miles apart
Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
<span>What you know: speed of the ships = 80 mph
Combined speed = 80+80 = 160 mph
Time = distance/combined speed -> time = 90/160 -> time = 0.56

</span>
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Solve the equation in the image
inn [45]

Answer:

x=73

Step-by-step explanation:

6 0
3 years ago
Help me guys <br> thx so much
navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
Read 2 more answers
Point T is on line segment \overline{SU} SU . Given ST=12ST=12 and TU=3,TU=3, determine the length \overline{SU}. SU
vova2212 [387]

Answer:

SU = 15

Step-by-step explanation:

Given that,

Point T is on line segment SU. So,

SU = ST + TU

Putting all the values, we get :

SU = 12 + 3

SU = 15

Hence, the length of SU is 15 units.

3 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
Sarah and Bryan went shopping and spent a total of $47.50 Bry an spent $15.50 less than what Sarah spent how much did bryan spen
Bogdan [553]
Since Bryan spent $15.50 less than Sarah, you would start by dividing the total amount they spent together in half.

$47.50 ÷ 2 = $23.75

Then you would take Bryan's 1/2 of the total and subtract $15.50.

$23.75 - $15.50 = $8.25

So, it looks like Bryan spent $8.25.

Check step:

If you add it all back together:

Sarah + Sarah Bryan = Total
$23.75 + $15.50 + $8.25 = $47.50
8 0
3 years ago
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