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Triss [41]
4 years ago
9

Construct two tangents to circle O, at A and at B, where AB is a diameter. What relationship exists between the two tangents?

Mathematics
1 answer:
hodyreva [135]4 years ago
7 0

Answer:

This two relationship exists :

A )  The two tangents from the point on circle to the exterior points are equal  in length

B ) The angle between a tangents and radius is right angles

Step-by-step explanation:

Given as ;

The circle with center O

The points A and B is on the circle

So, AB is the diameter of circle

Now, If we draw two tangents from point A and Points B , and  when we stretch both tangents to exterior point P , then at points P both will meet .

So, Two tangents AP  and  BP is constructed .

<u>From here if we measure the length of both tangents AP and BP , then the measure of both the lengths of tangents are equal .</u>

So , we can say that AP = BP

Again ,

<u>We can see that radius from the center O to the tangents makes right angle </u>

<u>I.e The on both tangents the radius is making equal angle i.e right angle </u>

Hence , From This two relationship exists :

A )  The two tangents from the point on circle to the exterior points are equal  in length

B ) The angle between a tangents and radius is right angles  

Answer

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Answer:

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Step-by-step explanation:

From the question we are told that

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    p = 0.96

Generally the mean is mathematically represented as

    \mu  =  n*  p

  => \mu  =  320 *  0.96

    => \mu  = 307.2

Generally the standard deviation is  

    \sigma =  \sqrt{n *  p *  (1 -p ) }

=>  \sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }

=> \sigma =3.50

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )

Here \frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )

=>P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )

Now applying  continuity correction we have

    P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )    

=>    P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )

=>    P(X  >300 ) =  P(Z >  -1.914 )

From the z-table  

    P(Z >  -1.914 ) =  0.97219

So

    P(X  >300 ) = 0.97219

8 0
3 years ago
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