Answer:
- first mechanic: $105/hour
- second mechanic: $55/hour
Step-by-step explanation:
Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...
20r +5(160-r) = 2375
15r +800 = 2375 . . . . . . eliminate parentheses
15r = 1575 . . . . . . . . . . . . subtract 800
r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.
160-r = 55 . . . . . Second mechanic's rate
The first mechanic charged $105 per hour; the second, $55 per hour.
Answer:
D. Subtract 4 from both sides
Explanation:
I just learned about quadratic equations in school. The first step of solving quadratic equations is to make sure it is in standard form and equal to 0.
Standard form:
ax^2 + bx + c = 0
Answer:
x = 1
Step-by-step explanation:
There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.
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Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.
(-2x +3) -(-3(-x) -2) = 0
A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...
-5x +5 = 0
So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.
<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)