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3 years ago

A) 2x-5y=10

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

5 0

Answer:

Step-by-step explanation:So to find it you need to eliminate either x or y. 2x-5y=10 over 4x-10y=20. In order to get y to eliminate you need one equation to have a positive 10y and a negetive 10y. So you multiply both sides of the first equation by negetive 2 so it is now, -4x+10y=-20. Notice how all the numbers in both equations are opposite this gives us ims infinitaly many sollutions. So it is not A. Or b it will do the same thing. The answer is either D or C hope this helps

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Can you write 12/20 as a fraction

natima [27]

You just did. or do you mean in simplest form?

8 0

3 years ago

Read 2 more answers

Can someone please help me in this question

Pie

Step-by-step explanation:

a) Let y = f(x) = 3x - 2x^2

f(-2) = 3(-2) - 2(-2)^2 = p

= -6 - 8

= -14

= p

f(2.5) = 3(2.5) - 2(2.5)^2 = q

= 7.5 - 12.5

= -5

= q

b) graphing

c) From the graph, you should be able to verify the following:

i) f(0.5) = 3(0.5) - 2(0.5)^2 = 1

ii) 0.5 = 3x - 2x^2 or x = 1.3, 0.2

iii) the maximum occurs at

f(0.75) = 1.125

d) the equation for the line of symmetry is x = 0.75

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3 years ago

Y= x^2 + 2 Find the slope of tangent line to graph when x= -1

ANTONII [103]

dy%2Fdx+=+6x%5E2 So the slope at x = 2 is 6*(2^2) = 24

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3 years ago

Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half

BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

$P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}$

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

$P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091$