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amid [387]
3 years ago
5

A) 2x-5y=10

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer:

Step-by-step explanation:So to find it you need to eliminate either x or y. 2x-5y=10 over 4x-10y=20. In order to get y to eliminate you need one equation to have a positive 10y and a negetive 10y. So you multiply both sides of the first equation by negetive 2 so it is now, -4x+10y=-20. Notice how all the numbers in both equations are opposite this gives us ims infinitaly many sollutions. So it is not A. Or b it will do the same thing. The answer is either D or C hope this helps

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27a+21 i need to solve thi problem help me
Anika [276]
That's an expression, so the only thing you can do is simplify it, but that already looks simplified.
8 0
3 years ago
a jar contains nickels and pennies. there are 56 coins in the jar in all. the total value of the coins is 1.52. how many pennies
nevsk [136]
1 penny is just 1c
one nickel is 5 pennies or 5c

alrite...

p = amount of pennies in the jar
n = amount of nickels in the jar

we know there are 56 coins in the jar, thus whatever "p" and "n" are,

p + n = 56

we also know, the total value of all pennies and nickels is one buck and 52 cents, or 1.52.. that's 152 pennies.

now, we know there are 5 pennies in one nickel, so in "n" nickels, there are 5*n pennies, or 5n, thus

p + 5n = 152

\bf \begin{cases}
p+n=56\implies \boxed{n}=56-p\\
p+5n=152\\
----------\\
p+5\left( \boxed{56-p} \right)=152
\end{cases}

solve for "p", to see how many penny coins are there.

what about the nickels? well, n = 56 - p.
5 0
3 years ago
HELP QUICK PLEASE<br> Determine the following values of the function.<br><br> f(-3) = <br> f(2) =
astra-53 [7]
F(-3) would be -8, because you would use the first equation. f(2) would be 4 apparently cause theres no x after the 4, or in the equation of the 4. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer(not necessarily mine). Thanks, it really helps! :D
4 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

What’s the question?

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