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AleksandrR [38]
3 years ago
11

Rolling two die, how many ways can a five show up on at least one die

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0
Total possibilities would be: 

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

You want 5 on at-least one, so mark 5th column & 5th raw.
There are 6 in both lines with 1 common = (5,5)

In short, Your Answer would be 11

Hope this helps!
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[ Answer ]

\boxed{=}

[ Explanation ]

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14 is equal to 14, therefore the __ (Or ?) is replaced with an = sign.

\boxed{[ \ Eclipsed \ ]}

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Step-by-step explanation:

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Relation 'B' IS NOT A FUNCTION

Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

Relation 'E' IS NOT A FUNCTION

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Thus, relation B is NOT a function.

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