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Dominik [7]
4 years ago
12

Which expression simplifies to 3x + 4z + 6?

Mathematics
1 answer:
Natalka [10]4 years ago
7 0

Answer:

7z + 3x + 6 - 3z

Step-by-step explanation:

7z - 3z = 4z

3x + 4z + 6

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QuestionA local road rises 30 feet for every 483 feet of highway. What is the slope of the highway?
max2010maxim [7]

The slope can be found by the "rise over run", that is, is the change in variable y divided by the change in variable x.

In this question,

\begin{gathered} slope=\frac{rise\text{ in the road}}{run\text{ in highway}} \\  \end{gathered}

Substituting the values:

\begin{gathered} slope=\frac{30}{483} \\ slope=0.06\text{ feet per feet of highway.} \end{gathered}

Answer: 0.06 feet per feet of highway.

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1 year ago
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Answer:

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Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
Solve the system of linear equations: 1/5 x + 1/8 y = 1 1/2 x − 1/3 y = 1
Alchen [17]

Answer:

x = 75 and y = -72

Step-by-step explanation:

It is given that,

1/5 x + 1/8 y = 1   ------(1)

1/2 x − 1/3 y = 1  -------(2)

<u>To find the solutions of the system of equations</u>

Step 1: eq(1) * 5 ⇒

x + 5/8y = 5  ----(3)

Step 2:  eq(2) * 2 ⇒

x - 2/3y = 2  -----(4)

Step 3: eq(3) - eq(4) ⇒

x + 5/8y = 5  ----(3)

<u>x - 2/3y = 2  -</u>----(4)

0 +(5/8 - 2/3)y = 3

 -1/24 y = 3

y = -24*3 = -72

Step 4: Substitute the value of y in eq(1)

1/5 x + 1/8 y = 1   ------(1)

1/5 x + 1/8 (-72) = 1   ------(1)

1/5 x  - 24 = 1

1/5 x = 25

x = 5*25 = 75

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4 0
3 years ago
Read 2 more answers
How do you solve the inequality 4w - 5 &lt; -10 + 3w
erik [133]
<span>4w - 5 < -10 + 3w
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w < -5</span>
4 0
3 years ago
the midpoint of kl is m(4.8, -7.8). one endpoint is l(0.6, -5.6). find the coordinates of the other endpoint k.
Vera_Pavlovna [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&k&(~ x &,& y~) &#10;%  (c,d)&#10;&l&(~ 0.6 &,& -5.6~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)

\bf \left( \cfrac{0.6+x}{2}~~,~~\cfrac{-5.6+y}{2} \right)~=~\stackrel{midpoint}{(4.8~,~-7.8)}\quad &#10;\begin{cases}&#10;\cfrac{0.6+x}{2}=4.8\\\\&#10;0.6+x=9.6\\&#10;\boxed{x=9}\\&#10;---------\\&#10;\cfrac{-5.6+y}{2}=-7.8\\\\&#10;-5.6+y=-15.6\\&#10;\boxed{y=10}&#10;\end{cases}
8 0
3 years ago
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