Answer:
d
Step-by-step explanation:
The given sample space S is
S={1,2,3,4,5,6}
The given event A and event B are
A={1,2} and B={3,4}.
As A and B have nothing in common i.e. A∩B={} thus, A and B are mutually exclusive.
As A and B are mutually exclusive then P(A or B) can be calculated as
P(A or B)=P(A)+P(B)-P(A∩B)
We know that if A and B are mutually exclusive events then P(A∩B)=0. So,
P(A or B)=P(A)+P(B)
In the given scenario
P(A)=n(A)/n(S)=2/6 and
P(B)=n(B)/n(S)=2/6
P(A or B)=2/6+2/6=4/6
P(A or B)=4/6
So, all the choices are correct