30 pages
We know that there are 60 minutes in an
hour, and that 3 goes into 60 20 times
(3/60 = 20). Multiply 1 1/2 x 20, and that
equals 30 pages.
You can also set it up in fraction form
multiply 1.5/3 times x/60. cross multiply and
solve for x. in this case x = 30.
Answer:
The percentage of visitors who are truthful clickers and answered yes is 15%.
Step-by-step explanation:
Denote the events as follows:
<em>Y</em> = a visitor clicked Yes.
<em>N</em> = a visitor clicked No.
<em>R</em> = a visitor is a random clicker.
<em>T</em> = a visitor is a truthful clicker.
Given:

The law of total probability states that:

The probability of Y can be computed using the law above as
Compute the value of P (Y|T) as follows:

Percentage = 0.15 × 100 = 15%.
Thus, the percentage of visitors who are truthful clickers and answered yes is 15%.
Answer: integer
Step-by-step explanation:
Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.