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asambeis [7]
3 years ago
9

-6-8(-8x-3) please help me and with how you did it

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

x = 9/32

Step-by-step explanation:

I believe you may have meant -6 equals, so here is how I did it

-6 = 8(-8x-3)

-6 = 64x - 24

64x = 18

x = 9/32

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A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence
belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

\mathbf{n = 5} --- the number of digits

\mathbf{r = 3} ---- the number of actions

Each of the three actions can either be:

  • <em>Pressing one button</em>
  • <em>Pressing a pair of buttons</em>

<em />

The number of ways of pressing a button is:

\mathbf{n_1 = ^5C_1}

Apply combination formula

\mathbf{n_1 = \frac{5!}{(5-1)!1!}}

\mathbf{n_1 = \frac{5!}{4!1!}}

\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}

\mathbf{n_1 = 5}

The number of ways of pressing a pair is:

\mathbf{n_2 = ^5C_2}

Apply combination formula

\mathbf{n_2 = \frac{5!}{(5-2)!2!}}

\mathbf{n_2 = \frac{5!}{3!2!}}

\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}

\mathbf{n_2 = 10}

So, the number of ways of performing one action is:

\mathbf{n =n_1 + n_2}

\mathbf{n =5 + 10}

\mathbf{n =15}

For the three actions, the number of ways is:

\mathbf{Action = n^3}

\mathbf{Action = 15^3}

\mathbf{Action = 3375}

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

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2 years ago
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Answer:

<h3>The answer is D.</h3>

Step-by-step explanation:

Explanation:

The rule of a triangle is that it the other two sides could not be longer than longest side of the triangle. If the two sides added up together is greater than the longest side, the triangle would no longer be connected. Since 8 + 12 ft still works for the longest side of the triangle, it will be considered the length of the third side.

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Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required
xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

                A = Pe^{rt}

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

               A = 2 × $3000

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               \frac{6000}{3000} = e^{0.085t}

               2 = e^{0.085t}

Take log_{e} of both sides

               log_{e}2 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln2 = 0.085t

               t = \frac{ln2}{0.085}

               t = \frac{0.693}{0.085}

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(b) For the amount to double, A = 3 × P

               A = 3 × $3000

               A = $9000

               9000 = 3000e^{0.085t}

               \frac{9000}{3000} = e^{0.085t}

               3 = e^{0.085t}

Take log_{e} of both sides

               log_{e}3 = log_{e}e^{0.085t}

But log_{e}e = 1

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               t = \frac{ln3}{0.085}

               t = \frac{1.0986}{0.085}

               t = 12.92

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3 years ago
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