If a diameter intersects a chord of a circle at a right angle, what conclusion can be made?
2 answers:
Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
You might be interested in
64x² - 36 factors to be (8x + 6)(8x - 6)
Option C is your answer.
HOWEVER, I cannot tell what the operation is supposed to be performed because of the way it is showing up above (see attached pic). So I can also just simplify it.
64x² - 36 becomes 4(16x² - 9) or 4(4x - 3)(4x + 3)
64x² + 36 becomes 4(16x² + 9)
Option C is your answer.
HOWEVER, I cannot tell what the operation is supposed to be performed because of the way it is showing up above (see attached pic). So I can also just simplify it.
64x² - 36 becomes 4(16x² - 9) or 4(4x - 3)(4x + 3)
64x² + 36 becomes 4(16x² + 9)