If a diameter intersects a chord of a circle at a right angle, what conclusion can be made?
2 answers:
Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
You might be interested in
Answer:
Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in
Step-by-step explanation:
Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.
Length = 24 in
Width = 18 in
Radius of the semi circle = Half of the width of the paperboard = = 9 in
1) Circumference of the semi circle = π*radius
= 3.14*9
= 28.26 in
2) Perimeter of the paperboard that remains after the semicircle is removed
= Top + Left + Bottom + Right Circumference of the semi circle
= 24 + 18 + 24 + 28.26
= 94.26 in
