Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
Answer:
x = 3
Step-by-step explanation:
The midsegment is half the sum of the parallel bases, that is
(3x + 3 + 4x + 2) = 13
(7x + 5) = 13 ( multiply both sides by 2 )
7x + 5 = 26 ( subtract 5 from both sides )
7x = 21 ( divide both sides by 7 )
x = 3