If a diameter intersects a chord of a circle at a right angle, what conclusion can be made?
2 answers:
Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
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Let f(x) = y.
y = 4x - 12
Let x = 0
y = 4(0) - 12
y = - 12
This leads to the point (0, -12).
Let y = 0.
0 = 4x - 12
1 2 = 4x
12/4 = x
3 = x
This leads to the point (3, 0).
We now graph both points and then connect each point with a straight line.
