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4 years ago

How do you determine if an ordered pair is a solution to an equation?

1 answer:

4 0

First follow the X axis and then follow the Y axis and then the points will meet so say you go over two and up three then your coordinates are 2,3

You might be interested in

An aquarium is to be drained. The aquarium is shaped like a rectangular prism with length 33 in , width 26 in , and height 12 in

artcher [175]

Answer:

To empty the aquarium it takes 26 minutes

Step-by-step explanation:

step 1

Find the volume of the aquarium

The volume of rectangular prism is

$V=LWH$

we have

$L=33\ in\\W=26\ in\\H=12\ in$

substitute the given values

$V=(33)(26)(12)=10,296\ in^3$

step 2

Divide the volume by the rate of 396 in^3 per minute

$10,296/(396)=26\ minutes$

therefore

To empty the aquarium it takes 26 minutes

3 0

3 years ago

elixir [45]

Answer:

1st Question Answer: y = -2x-3=

x=−1/2 y+ −3/2

2nd Question y = 2x - 1

Answer: x=1/2y+1/2

3rd Question : y = x + 4

Answer: x=y−4

4th Question: YX+2

Answer: xy+2

5th Question:y = -2x - 3

Answer: -2x - 3

6th Question: y = x +4

Answer: x=y−4

7th Question: y = 2x-1

Answer: x=1/2y+1/2

8th Question:y = -x + 2

Answer: x=−y+2

Step-by-step explanation:

Hope this helps :)

PLS BRAINLIEST I TOOK LONG TO COMPLETE THIS

6 0

3 years ago

A restaurant served 576 meals at lunch. It then served 52 meals at dinner. How many meals did it serve in all?

Keith_Richards [23]

576+52=
628
So, the restaurant sold 628 meals in all.

3 0

3 years ago

Read 2 more answers

Kennedy buys cell phone cases for $4.50 and sells them to her friends for $18.00. What is the percent mark-up?

lidiya [134]

300% markup is the answer

7 0

3 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

lara31 [8.8K]

Answer:

The sample size is 1875.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

Sampling error of 0.03.

This means that $M = 0.03$

99.74% confidence level

So $\alpha = 0.0026$ , z is the value of Z that has a pvalue of $1 - \frac{0.0026}{2} = 0.9987$ , so $Z = 3$ .

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

What is the sample size

The sample size is n. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 3\sqrt{\frac{0.25*0.75}{n}}$

$0.03\sqrt{n} = 3\sqrt{0.25*0.75}$

Simplifying by 0.03 both sides

$\sqrt{n} = 100\sqrt{0.25*0.75}$

$(\sqrt{n})^2 = (100\sqrt{0.25*0.75})^2$

$n = 1875$

The sample size is 1875.

7 0

3 years ago