Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.
Answer:
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Answer:
(2, - 3 )
Step-by-step explanation:
Given the 2 equations
y = - 3x + 3 → (2)
y = - 9x + 15 → (2)
Substitute y = - 3x + 3 into (2)
- 3x + 3 = - 9x + 15 ( add 9x to both sides )
6x + 3 = 15 ( subtract 3 from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
Substitute x = 2 into either of the 2 equations and solve for y
Substituting into (1)
y = - 3(2) + 3 = - 6 + 3 = - 3
solution is (2, - 3 )
Writing the two equations in full and subtracting R(x) from W(x) to arrive at D (x) gives the answer. This is shown below;
W(x) = 0.002x^3 - 0.01x^2 + 0x + 0
R (x) = 0x^3 + x^2 - 4x +13 -
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D(x) = 0.002x^3 -1.01x^2 + 4x - 13
Answer:
x + 2 = y
Step-by-step explanation:
y = x - 2
x = y - 2
x + 2 = y
