Well since we’re given 2 angles, 62 and 58, we have enough information to solve the problem.
Since any triangles angles always add up to 180 degrees, we can simply add up 62 and 58 then subtract from 180.
62
+58
———
120
Now to find the last angle of the triangle you have to subtract 120 from 180 which is 60 degrees. This means x = 60.
However we’re not done, with this 60 we can now calculate y. Since the line is a 180 angle line! We can just subtract 60 from 180 which gives us 120.
The angle of y is 120
We have that
y = −14x² − 2x − 2
First, we need to transform the equation into its vertex form
(x - h)²=4p(y - k)
<span>Group
terms that contain the same variable
</span>y = (−14x² − 2x )− 2
<span>Factor the
leading coefficient
</span>y = -14*(x² + (2/14)x )− 2
<span>Complete
the square Remember to balance the equation
</span>y = -14*(x² + (2/14)x +(2/28)²-(2/28)²)− 2
y = -14*(x² + (2/14)x +(2/28)²)− 2+14*(2/28)²
y = -14*(x² + (2/14)x +(2/28)²)− 2+56/784
Rewrite as perfect squares
y = -14*(x+(2/28))²− 1512/784------>(x+1/14)²=(-1/14)*(y+1512/784)
4p=-1/14------> p=-1/56
This is a vertical parabola and its focus <span>(h, k + p)</span>
<span>h=-1/14</span>
<span>k+p=(-1512/784)+(-1/56)----> (-1512-14)/784)----> -1526/784</span>
<span>
</span>
<span>the focus is</span>
<span>(-1/14,-1526/784)</span>
Answer:
It's graph D
Step-by-step explanation:
Answer/Step-by-step explanation:
A. Distance travelled at constant rate = 180 miles
Rate of travel (r) = distance travelled (d) /time (t)
Travel time (hrs) ==> rate of travel (miles/hr)
5 ==> 180/5 = 36
4.5 ==> 180/4.5 = 40
3 ==> 180/3 = 60
2.25 ==> 180/2.25 = 80
B. t = time travelled in hrs,
r = rate (miles/hr)
d = distance travelled = 180
Therefore, rate travelled for t hours would be:
