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Anestetic [448]
3 years ago
7

What is volume of a cylinder with a. Radius of 7 and a height of 3

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:v=461.81

Step-by-step explanation:

V=pi*r^2h

V=pi*7^2*3=461.81

Hope I helped :)

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Biometric measures evaluate: Question 17 options: data about a person's heartbeat, perspiration levels, respiration, and body mo
olga2289 [7]

Answer:

data about a person's heartbeat, perspiration levels, respiration, and body movements.

Step-by-step explanation:

the answer to the question is that

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3 years ago
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eduard

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C

Step-by-step explanation:

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3 years ago
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A bus makes a stop at 2:30, letting off 15 people and letting on 9. The bus makes another stop ten minutes later to let off 4 mo
nika2105 [10]
(-19)+9=-10, so there is 10 less people on the bus

4 0
3 years ago
Read 2 more answers
Please help!!
yarga [219]

Because this is a fourth degree that will be tricky to factor as it is, we will do a u substitution. Let x^2=u. We can now rewrite that polynomial in terms of u: u^2-7u-8=0. Filling into the quadratic formula we have u=\frac{7+/-\sqrt{49-4(1)(-8)}}{2}. Simplifying down u=\frac{7+/-\sqrt{81}}{2} and u=\frac{7+9}{2} or u=\frac{7-9}{2}. That means that u = 8 or u = -1. But don't forget that we let u=x^2, so we have to put x-squared back in for u. That gives us x^2=8 which simplifies down to +/-2\sqrt{2}. That also gives us x^2=-1. When we take the square root of -1, we have to use the fact that -1 = i^2, so we sub that in to get x=+/-i. All in all, your solutions are as follows: 2\sqrt{2},-2\sqrt{2},i,-i which is choice b.

7 0
3 years ago
What is 5p to the -7 power/20p to the 2 power simplified
mr_godi [17]

Answer:

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Step-by-step explanation:

Here we have:

  (5p)^(-7)

----------------

   (20p)^2

Let's temporarily remove the coefficient 5/20 and reduce it to 1/4.

then we have:

            1                             1               1

(1/4) -------------  = (1/4) -------------- = ------------

       p^7*p^2               p^(7 + 2)         p^9

8 0
3 years ago
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