3 years ago

The value of n for the equation 5n = 5 11 × 5 3

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

3 0

If you add the two terms on the right, you will get 5^14. 14 is your answer.

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If 3/4 of the class likes soda and 3/5 of those who like soda prefer Coke, what PERCENT of the whole class that likes Coke?

katen-ka-za [31]

Answer:

For soda =3/4

For coke= 3/5 X 3/4=9/20

Whole class is 1....

Therefore X% of 1 =9/20

Solving :

X/100 X 1 =9/20

X/100=9/20

20X =900

X= 900/20 = 45%

8 0

3 years ago

Factor the expression completely over the complex numbers.<br><br> x4−625

marusya05 [52]

Your factoring answer is: (x^2+25)(x+5)(x-5)

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4 years ago

1 5/16 + 1 5/16=_____

algol13

Answer:

2 10/16 or 2 5/8

Step-by-step explanation:

You can add the whole numbers first, so 1+1=2

Now add the remaining fractions: 5/16 +5/16=10/16.

2+10/16=2 10/16 or 2 5/8.

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3 years ago

Find the quotient of the quantity negative 12 times x to the 3rd power plus 21 times x to the 2nd power minus 6 times x all over

PIT_PIT [208]

The correct answer would be A

7 0

4 years ago

Read 2 more answers

Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$

The probability is 0.5798 or 57.98%.

8 0

3 years ago