Answer:
the number of of litres of paint to the nearest litre for 1000 bars is 1 litre
Step-by-step explanation:
Given that:
1000 cylindrical metal bars have :
a length of 120 m
and a diameter of 0.2 m
The volume of the cylindrical bar can be calculated by the formula:
where ;
radius 
r = 0.1 m
the length of the cylindrical metal bars is equal to the height of the metal bar = 120 m
Thus the volume can now be calculated as follows:
V = 3.77 m³
So; from the given information.
One litre of paint will cover 4m³
and we want to find how many litres of paint will be used for the 1000 cylindrical bars.
If 1 litre = 4m³
Then x litre = 3.77 m³
4x = 1 × 3.77
x = 0.9425 litres
x = 1 litres to the nearest litres.
Thus ; the number of of litres of paint to the nearest litre for 1000 bars is 1 litre
Answer:
Step-by-step explanation:
This only happens with right triangles. You need only 2 legs. The reason is that the two legs given are the arms of the right angle so secretly you are using SAS. The right angle is enclosed by the two legs, and that must be stated among your givens.
So the answer to the question is true.
Answer:
0
Step-by-step explanation:
500-10= 490 you will need $490 dollars more sorry man save up maybe in the future
Its B on edgeuity just took the quiz
(s is greater or equal than 4)
Answer:
Given the series,
∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1
I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)
So,
∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞
There are different types of test to show if a series converges or diverges
So, using Ratio test
Lim n → ∞ (a_n+1 / a_n)
Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))
Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))
Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)
Lim n→ ∞ (-1/2)^(n-n+1)
Lim n→ ∞ (-1/2)^1 = -1/2
Since the limit is less than 0, then, the series converge...
Sum to infinity
Using geometric progression formula
S∞ = a / 1 - r
Where
a is first term
r is common ratio
So, first term is
a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1
a_1 = -4
Common ratio r = a_2 / a_1
a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2
a_2 = 2
Then,
r = a_2 / a_1 = 2 / -4 = -½
S∞ = -4 / 1--½
S∞ = -4 / 1 + ½
S∞ = -4 / 3/2 = -4 × 2 / 3
S∞ = -8 / 3 = -2⅔
The sum to infinity is -2.67 or -2⅔
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Step-by-step explanation: PHEW THAT TOOK A WHILE LOL IM A FAST TYPER</h2>
