Answer:
$144.70
Step-by-step explanation:
Calculation to determine how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization
First step is to determine the Interest only monthly repayments
Using this formula
I=Prt
where,
P=$6925
r=0.05/1
t=1
Let plug in the formula
I=6925*0.05/12
I= $28.854166666
Second step is to determine the amount she will owe after 4 years
Using this formula
S=P(1+r)n
Let plug in the formula
S=6925*(1+0.05/12)4*12
S=6925*(1+0.05/12)48
S=$8454.70
Third step is to determine the Interest part
Interest =8454.70 - 6925
Interest = $1529.70
Now let determine the how much greater will the amount of interest capitalized be
Interest capitalized=1529.70 - 1385.00
Interest capitalized =$144.70
Therefore how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization is $144.70
The sum is 41.22 because first you turn all of the fractions into decimals and then it’s easier to add them all together all at once.
Answer:
Step-by-step explanation:
To do this, you must substitute 
for x in the equation g(x)
Simplified this would be
3/10 <7/8
Please my answer
<span>The factors of 60 are 60, 30, 20, 15, 12, 10, 6, 5, 4, 3, 2, 1.The factors of 75 are 75, 25, 15, 5, 3, 1.<span>The common factors of 60 and 75 are 15, 5, 3, 1, intersecting the two sets above.</span><span>In the intersection factors of 60 ∩ factors of 75 the greatest element is 15.</span><span>Therefore, the greatest common factor of 60 and 75 is 15.
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