By default, Outlook orders messages in the Content pane grouped by dates the messages were received and sorted with the oldest message at the top of the list.

Explanation:

8 0

2 years ago

TULPCOAONIAC TRUOESP this is un scrambled word

MaRussiya [10]

Answer:

1.)OCCUPATIONAL

2.)POSTURE

This is the answer thank youu!♡︎♡︎

4 0

2 years ago

Read 2 more answers

Your mother is sure that you were driving too fast because she knows

Klio2033 [76]

I think the corret answer would be C

5 0

3 years ago

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let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest va

Ahat [919]

Answer:

Explanation:

From the given information:

$a_{n-1} , a_{n-2}...a_o$ in binary is:

$a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o$

So, the largest number posses all $a_{n-1} , a_{n-2}...a_o$ nonzero, however, the smallest number has $a_{n-2} , a_{n-3}...a_o$ all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

$(11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}$

$= \dfrac{1(2^n-1)}{2-1}$

$\mathbf{=2^n -1}$

$(1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}$

$\mathbf {= 2 ^{n-1}}$

Hence, the smallest value is $\mathbf{2^{n-1}}$ and the largest value is $\mathbf{2^{n}-1}$

3 0

2 years ago