3 I think 1 2 3 would be it
Answer:
whT type of question is this
Step-by-step explanation:
![A =(125^{2} + 25^{2} ) (5^{2} - 1)\\A = [(5^{3})^{2} + (5^{2})^{2} ] . (5^{2} - 1)\\A = (5^{6} + 5^{4} ). (5^{2} - 1)\\A = [5^{4} . ( 5^{2} + 5)].(5^{2} - 1) \\A = 5^{4} . (25+ 5). (5^{2} - 1)\\A = 5^{4} . 30. (5^{2} - 1)\\](https://tex.z-dn.net/?f=A%20%3D%28125%5E%7B2%7D%20%2B%2025%5E%7B2%7D%20%29%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%5B%285%5E%7B3%7D%29%5E%7B2%7D%20%20%2B%20%285%5E%7B2%7D%29%5E%7B2%7D%20%5D%20.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%285%5E%7B6%7D%20%20%2B%205%5E%7B4%7D%20%29.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%5B5%5E%7B4%7D%20.%20%28%205%5E%7B2%7D%20%20%2B%205%29%5D.%285%5E%7B2%7D%20-%201%29%20%5C%5CA%20%3D%205%5E%7B4%7D%20.%20%2825%2B%205%29.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%205%5E%7B4%7D%20.%2030.%20%285%5E%7B2%7D%20-%201%29%5C%5C)
Since 30 is divisible by 3
Thus, A is divisible by 3
Good luck!
They give you what you have to use on side of the paper and at the very bottom it said divide and now you use that and you will get your answer to your problem
Work is shown (^_^)
Did #9-10 also
3) 3p -2 = -29 Isolate 3
3p= -29+2
3p= -27 Divide by 3
p = -9
4) 1- r = -5 Isolate r
-r= -5-1
-r= -6 Multiply by -1
r= 6
5) k-10/2 = -7 Multiply by 2
k-10= 2(-7)
k-10= -14
k=-14+10
k=-4
See attached file for #6-10
<span />