For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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A = π r^2
A = 9^2 <span>π
</span>A = 81<span>π
if using </span>π = 3.14 then
A = 3.14 x 81 = 254.47 ft^2
answer: 81π ft^2 or 254.47 ft^2
hope that helps
Answe8 times 8 equal 69 and bla ba
Step-by-step explanation:
Answer:
The correct answer is y = 12x + 9
Step-by-step explanation:
There is a formula called y = mx + b where m is the slope and b is the y-intercept
The y-intercept is 9 so y = mx + 9
The slope is 12/1 or just 12 so y = 12x + 9
Answer:
Step-by-step explanation:
Given function is,
f(x) = 
If the given function is vertically stretched by a scale factor of 
Or 1.5,
Transformed function will be,
h(x) = ![\frac{3}{2}[f(x)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bf%28x%29%5D)
h(x) = 
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) = 
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of then shifted 1 unit upward.
