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Nana76 [90]
3 years ago
9

May someone please help me out with this problem? May you also explain it?

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

Step-by-step explanation:

Given function is,

f(x) = \sqrt{x}

If the given function is vertically stretched by a scale factor of \frac{3}{2} Or 1.5,

Transformed function will be,

h(x) = \frac{3}{2}[f(x)]

h(x) = \frac{3}{2}(\sqrt{x})

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = \frac{3}{2}(\sqrt{x} )+1

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of \frac{3}{2} then shifted 1 unit upward.

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What two numbers add up to 18 and multiply to 80
mestny [16]

Answer:

8 and 10

Step-by-step explanation:

First, let's look at the factors of 80.

1 • 80 = 80

2 • 40 = 80

4 • 20 = 80

5 • 16 = 80

8 • 10 = 80

Look at each pair and evaluate their sum.

1 • 80 = 80

  • 1 + 80 = 81

2 • 40 = 80

  • 2 + 40 = 42

4 • 20 = 80

  • 4 + 20 = 24

5 • 16 = 80

  • 5 + 16 = 21

8 • 10 = 80

  • 8 + 10 = 18

Our last pairing multiplies to 80 and adds up to 18. Therefore, your answer is 8 & 10.

Hope this helps!

4 0
2 years ago
Find the sum of -3a + 2 and 5a - 3
Anon25 [30]

Answer

-1(3a-2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The value of y varies directly with x. If x = 6, then y = 27. What is the value of y when x = 10 ?
Alik [6]
B - 45 because 27 divided by 6 is 4.5 and then 10x4.5=44
7 0
2 years ago
Is the data set approximately periodic?
wolverine [178]

Answer:

Option: C is the correct answer.

       C. Periodic with period 4 and amplitude of about 15.

Step-by-step explanation:

We are given the table of values as:

Hour             1 -- 2 -- 3 --  4 --  5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11

Number       24-41-10-32-26-38-9-31-25-39-12

of boats

As we could see that after every 4 value the values are approximately repeating.

Hence,the data set is approximately periodic.

Also, the amplitude is calculated as:

Average of the maximum and minimum value of each set

We divide the set into 3 sets as follows:

 Hour                       1           2           3            4

Number of boat      24        41          10           32

Here we have amplitude as:

         (41-10)/2=15.5

 Hour                       5           6           7            8

Number of boat      26        38           9           31

  Amplitude is:

          (38-9)/2=14.5

Hour                       9           10          11            12

Number of boat      25        39          12      

            Amplitude is:

            (39-12)/2=13.5

Hence, we see that the amplitude is about 15.

   

4 0
3 years ago
Which is greater, 5/4 or 3/2?
Sliva [168]
3/2 is the right answer
5 0
3 years ago
Read 2 more answers
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