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Nana76 [90]
3 years ago
9

May someone please help me out with this problem? May you also explain it?

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

Step-by-step explanation:

Given function is,

f(x) = \sqrt{x}

If the given function is vertically stretched by a scale factor of \frac{3}{2} Or 1.5,

Transformed function will be,

h(x) = \frac{3}{2}[f(x)]

h(x) = \frac{3}{2}(\sqrt{x})

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = \frac{3}{2}(\sqrt{x} )+1

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of \frac{3}{2} then shifted 1 unit upward.

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A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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