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2 years ago

May someone please help me out with this problem? May you also explain it?

Mathematics

1 answer:

gavmur [86]2 years ago

3 0

Answer:

Step-by-step explanation:

Given function is,

f(x) = $\sqrt{x}$

If the given function is vertically stretched by a scale factor of $\frac{3}{2}$ Or 1.5,

Transformed function will be,

h(x) = $\frac{3}{2}[f(x)]$

h(x) = $\frac{3}{2}(\sqrt{x})$

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = $\frac{3}{2}(\sqrt{x} )+1$

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of $\frac{3}{2}$ then shifted 1 unit upward.

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38: it's a right triangle
39:
area:
$a = \pi {r}^{2}$
$a = 3.14 \times {10}^{2} = 314$

circumference:
$c = \pi \times diameter$
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