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Maslowich
3 years ago
13

Can somebody help me with this problem

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0
Top right, only works for right triangles
astraxan [27]3 years ago
4 0
The one in the bottom right hand corner 
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X^2 - 25 = (x + 5) (?)
mixas84 [53]

Answer:

(?) = (x-5)

Step-by-step explanation:

Use difference of squares:

x^2-25=(x+5)(x-5)

5 0
4 years ago
What is the produce of 1 2/3 and -3 1/2
katrin [286]
12/3 is 4 and .31/2 is -15.5
8 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST!!!!!!
katovenus [111]

Answer:

I think Quadrant 1. I;m not trying to just answer for the points

Step-by-step explanation:

5 0
3 years ago
Ryan, a baker, measured the weights of cakes baked in each batch at his bakery and found that the mean weight of each cake is 50
denpristay [2]

Answer: Rejecting the mean weight of each cake as 500 gram when H subscript 0 equals 500

Step-by-step explanation:

Given that :

Null hypothesis : H0 =500

Alternative hypothesis : Ha < 500

Type 1 Error: Type 1 error simply occurs when we reject the Null hypothesis when the Null is true. Alternatively, type 11 error occurs when we fail to reject a false null hypothesis.

Hence, in the scenario above, a type 1 error will occur when we reject the mean weight as 500 even though the Null hypothesis is True.

6 0
4 years ago
Binomial ( 5x - y ) ^ 10 terms ax ^ 2 y ^8
iragen [17]
\bf (5x-y)^{10}\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&+1&(5x)^{10}(-y)^0\\&#10;2&+10&(5x)^9(-y)^1\\&#10;3&+45&(5x)^8(-y)^2\\&#10;4&+120&(5x)^7(-y)^3\\&#10;5&+210&(5x)^6(-y)^4\\&#10;6&+252&(5x)^5(-y)^5\\&#10;7&+210&(5x)^4(-y)^6\\&#10;8&+120&(5x)^3(-y)^7\\ 9&+45&(5x)^2(-y)^8&#10;\end{array}

now, how do we get the coefficients?  well, the first coefficient is 1, any subsequent is " the product of the current terms's coefficient and the exponent of the first element, divided by the exponent of the second element in the next term", now that's a mouthful, but for example,

how did get 210 for the 5th expanded term?  well is just 120 * 7 / 4

how about 252 of the 6th term?   210 * 6 / 5.

how about 45 of the 9th one?  120 * 3 / 8.

of course, the exponents for each is simple, as you'd already know from the binomial theorem.

so, just expand away the 9th expanded term.
3 0
3 years ago
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