<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
7 hundredths
Step-by-step explanation:
add 4 to 6 and take away 3
Answer:
- 2/5x=7/20x+1/4
- -3/4=-1/20x-1/2
- -3/4+1/20x=-1/2
Step-by-step explanation:
If you add 3/4 to both sides of the equation, you get ...
... 2/5x = 7/20x + 1/4 . . . . first choice
If you subtract 2/5x from both sides of the equation, you get ...
... -3/4 = -1/20x -1/2 . . . . third choice
If you subtract 7/20x from both sides of the equation, you get ...
... -3/4 +1/20x = -1/2 . . . . last choice
Choices 2 and 4 are erroneous versions of choices 1 and 3, so do not apply.
Answer:
The points of the rotated shape are: (4, 1), (5, 3), (4, 4), (2, 1), (1, 3), (2, 4)
Step-by-step explanation:
From the part of the shape we can see and the symmetry, the missing points are:
(-2, -1)
(-1, -3)
(-2, -4)
Rotation 180° about the origin transforms the point (x, y) into (-x, -y). Applying this rule to our figure, we get:
(-4, -1) -> (4, 1)
(-5, -3) -> (5, 3)
(-4, -4) -> (4, 4)
(-2, -1) -> (2, 1)
(-1, -3) -> (1, 3)
(-2, -4) -> (2, 4)
If we take for example 20x1.5=30 the scale factor would create an enlargement
