Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
It will be irrational. The sum of any irrational and rational number will ALWAYS result in a irrational answer. Khan Academy has a video on this if you want to watch it.
Answer:
A. A = B
Step-by-step explanation:
Given
Required
Which of the options is true
We start by simplifying
Permutation is calculated as follows
So.
0! = 1; So
Hence. B! = P!
<em>This implies that </em>
<em />
Answer:
Cost of a pound of chocolate chips: $3.5
Cost of a pound of walnuts: $1.25
Step-by-step explanation:
x - cost of a pound of chocolate chips
y - cost of a pound of walnuts
We create two equations based on the information we have:
3x+2y=13
8x+4y=33
The whole point of these problems os to get rid of x or y. In this question, we can do this by multiplying both sides of the first equation by 2, and then subtracting it from the second equation:
8x+4y=33
6x+4y=26
2x=7
x=3.5
Then we change x for 3.5 in the first equation:
3×3.5+2y=13
10.5+2y=13
2y=2.5
y=1.25
Hope this helps!
