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Yuri [45]
3 years ago
5

PLEASE HELP, ITS URGENT!​

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

A. 3y+1

that is the answer

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C <br> 5 in<br> 4 in<br> What is the length of the hypotenuse?
vlabodo [156]

Answer:

{c}^{2}  =  {5}^{2}  +  {4}^{2}  \\   {c}^{2}  = 25 + 16 \\  {c}^{2} = 41

3 0
3 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
Group of answer choices<br><br> Phone A<br><br> Phone B<br><br> Phone C<br><br> Phone D
Otrada [13]

Answer:

Phone B

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How many years (approximately) will it take $6,000 to amount $8,000 if it is invested at an annual rate of 9.0% compounded conti
quester [9]

Answer:

It should take roughly 3.5 years

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Andy estimated that he would need 75 feet of lumber for a tree house project. he later found that the actual amount of lumber ne
Kipish [7]
Step 1
<span>Calculate the error
</span>error=75-64-----> 11 ft

step 2
<span>Divide the error by the exact value
</span>11/64=0.1719

step 3
<span>Convert that to a percentage 
</span>0.1719*100=17.19%

the answer is
17.19%

8 0
3 years ago
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