3 years ago

PLEASE HELP, ITS URGENT!

Mathematics

1 answer:

Len [333]3 years ago

8 0

Answer:

A. 3y+1

that is the answer

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C 5 in 4 in What is the length of the hypotenuse?

vlabodo [156]

Answer:

${c}^{2} = {5}^{2} + {4}^{2} \\ {c}^{2} = 25 + 16 \\ {c}^{2} = 41$

3 0

3 years ago

Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

7 0

3 years ago

Group of answer choices Phone A Phone B Phone C Phone D

Otrada [13]

Answer:

Phone B

Step-by-step explanation:

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3 years ago

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How many years (approximately) will it take $6,000 to amount $8,000 if it is invested at an annual rate of 9.0% compounded conti

quester [9]

Answer:

It should take roughly 3.5 years

Step-by-step explanation:

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3 years ago

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Andy estimated that he would need 75 feet of lumber for a tree house project. he later found that the actual amount of lumber ne

Kipish [7]

Step 1
Calculate the error
error=75-64-----> 11 ft

step 2
Divide the error by the exact value
11/64=0.1719

step 3
Convert that to a percentage
0.1719*100=17.19%

the answer is
17.19%

8 0

3 years ago

PLEASE HELP, ITS URGENT!​

PLEASE HELP, ITS URGENT!