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Alex_Xolod [135]
4 years ago
7

Outputting all combinations. Output all combinations of character variables a, b, and c using this ordering abc acb bac bca cab

cba.
If a = 'x', b = 'y', and c = 'z', then the output is: xyz xzy yxz yzx zxy zyx
Your code will be tested in three different programs, with a, b, c assigned with 'x', 'y', 'z', then with '#', '$', '%', then with '1', '2', '3'.

#include
using namespace std;
int main()
{
char a; char b; char c;
cin >> a; cin >> b; cin >> c;
/* Your solution goes here */
cout << endl;
return 0;
}
Computers and Technology
1 answer:
Alina [70]4 years ago
5 0

Answer:

#include<iostream>

using namespace std;

 

int main()

{

   char a;  

   char b;  

   char c;

cin >> a;  

cin >> b;  

cin >> c;

 cout<<a<<b<<c<<endl;

 cout<<a<<c<<b<<endl;

 cout<<b<<a<<c<<endl;

 cout<<b<<c<<a<<endl;

 cout<<c<<a<<b<<endl;

 cout<<c<<b<<a<<endl;

 

cout << endl;

}

Explanation:

Note: code is hard coded it does not contain any logic based coding

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Which of the following loop conditions will read all the data in the file assuming that each line in the file contains two integ
PSYCHO15rus [73]

Answer:

while(inFile >> intOne >> intTwo)

Explanation:

Options are missing but the line of code that does the illustration in the question is while(inFile >> intOne >> intTwo)

Considering two variables, intOne and intTwo

Suppose that a file location has been specified, the infile statement identifies file which could either be an external data or an in-stream data from which data should be read.

while(inFile >> intOne >> intTwo)

Declares a while loop, with the help of the inFile statement, values in the first column are entered into intOne while the second column are entered into intTwo through with the help of then input channel symbol (>>).

3 0
4 years ago
CHANGE POSITION OF SONG Enter song's current position: Enter new position for song: "Peg" moved to position 3 JAMZ PLAYLIST MENU
hichkok12 [17]

Answer:

Answers can be found below

Explanation:

port java.util.Scanner;

public class Playlist {

String title;

SongEntry head;

public Playlist(String title) {

this.title = title;

this.head = null;

}

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

System.out.println("Enter the playlist's title:");

String title = scanner.nextLine();

Playlist playList = new Playlist(title);

String option;

do {

option = playList.printMenu(scanner);

switch (option) {

case "a":

playList.addSong(scanner);

break;

case "d":

playList.removeSong(scanner);

break;

case "c":

playList.changePosition(scanner);

break;

case "s":

playList.outputSongByArtist(scanner);

break;

case "t":

playList.outpuTotalTime();

break;

case "o":

playList.outputFullPlayList();

break;

case "q":

System.out.println("QUIT");

break;

default:

System.out.println("please enter a valid option");

}

} while (!option.equals("q"));

}

public String printMenu(Scanner scanner) {

System.out.println(this.title + " PLAYLIST MENU");

System.out.println("a - Add song");

System.out.println("d - Remove song");

System.out.println("c - Change position of song");

System.out.println("s - Output songs by specific artist");

System.out.println("t - Output total time of playlist (in seconds)");

System.out.println("o - Output full playlist");

System.out.println("q - Quit");

System.out.println("Choose an option:");

String input = scanner.nextLine();

return input;

}

public void outputFullPlayList() {

if (head == null) {

System.out.println("Playlist is empty");

} else {

SongEntry tempNode = head;

while (tempNode != null) {

tempNode.printPlaylistSongs();

tempNode = tempNode.getNextNode();

}

}

}

public void addSong(Scanner scanner) {

System.out.println("ADD SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

System.out.println("Enter song's name:");

String songName = scanner.nextLine();

System.out.println("Enter artist's name:");

String artistName = scanner.nextLine();

System.out.println("Enter song's length (in seconds):");

int length = Integer.parseInt(scanner.nextLine());

SongEntry song = new SongEntry(uniqueId, songName, artistName, length);

if (head == null) {

head = song;

} else {

SongEntry tempNode = head;

while (tempNode.getNextNode() != null) {

tempNode = tempNode.getNextNode();

}

tempNode.insertAfter(song);

}

}

public void removeSong(Scanner scanner) {

System.out.println("REMOVE SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

SongEntry tempNode1 = head;

SongEntry tempNode2 = head;

while (tempNode1 != null) {

if (tempNode1.getUniqueID().equals(uniqueId)) {

if (tempNode1.getUniqueID().equals(head.getUniqueID())) {

6 0
4 years ago
An application with which you can perform calculations on numbers and work with other data
zhannawk [14.2K]
Microsoft Excel or another spreadsheet program.
6 0
4 years ago
Write the method makeNames that creates and returns a String array of new names based on the method’s two parameter arrays, arra
Gwar [14]

Answer:

  1. import java.util.Arrays;
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        String [] first = {"David", "Mike", "Katie", "Lucy"};
  5.        String [] middle = {"A", "B", "C", "D"};
  6.        String [] names = makeNames(first, middle);
  7.        System.out.println(Arrays.toString(names));
  8.    }
  9.    public static String [] makeNames(String [] array1, String [] array2){
  10.           if(array1.length == 0){
  11.               return array1;
  12.           }
  13.           if(array2.length == 0){
  14.               return array2;
  15.           }
  16.           String [] newNames = new String[array1.length];
  17.           for(int i=0; i < array1.length; i++){
  18.               newNames[i] = array1[i] + " " + array2[i];
  19.           }
  20.           return newNames;
  21.    }
  22. }

Explanation:

The solution code is written in Java.

Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).

In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]

5 0
3 years ago
What property of semi-metals is useful in the computer industry?
artcher [175]
The answer is (a. Semi-conducting)
In the computer industry, semi-metals with a semiconducting property are useful in making of semiconductors. These metals have high resistance but lower than compare to insulators. This conductor could be crystalline or amorphous solids.
4 0
3 years ago
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