Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Answer:
False
Explanation:
The answer to this question is false. This is because the NVD doesn't perform such tests on their own. Instead they they rely on third-party vendors, software researchers, etc to get such reports and do the assignment of CVSS scores for softwares
The National Vulnerability Database (NVD) is the United State governments leading resource for software vulnerability
You should boot into <u>safe mode</u> and disable the device or service when it causes the computer system to hang during a normal boot.
<h3>What is
safe mood?</h3>
Safe mood can be defined as a boot option in which the operating system (OS) of a computer system starts in <u>diagnostic mode</u> rather than in a normal operating mode, so as to enable the user correct any problems preventing the computer system to have a normal boot.
This ultimately implies that, safe mood is a diagnostic mode of the operating system (OS) of a computer system that is designed and developed to fix most problems within an operating system (OS) and for the removal of rogue software applications.
Read more on safe mood here: brainly.com/question/13026618
Yes uo daddddy deff uuxk me. har we. dd dads aafddu
Answer:
#include <iostream>
using namespace std;
int main()
{
string str;
cout<<"Enter the string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++){
if(str[i]=='e'){
str[i]='x';
}
}
cout<<"the string is: "<<str<<endl;
return 0;
}
Explanation:
First, include the library iostream for using the input/output instructions.
Create the main function and declare the variables.
Then, use the cout instruction and print the message on the screen.
cin store the string enter by the user into a variable.
After that, take a for loop and if-else statement for checking the condition if the string contains the 'e', then change that alphabet to 'x'.
This process continues until the string not empty.
Finally, print the updated string.