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3 years ago

Which of the following are factors of x^4 – 16? Select all that apply.

Mathematics

2 answers:

Alex73 [517]3 years ago

7 0

Answer:

A and D.

Step-by-step explanation:

$x^4 -16$

$(x^3+2x^2+4x+8)(x-2)$

$(x^2+4)(x+2)(x-2)$

nekit [7.7K]3 years ago

5 0

<h2>Answer:</h2><h2>x^2+4 and X+2</h2>

Solution,

x^4-16

= (X^2)^2-(4)^2

Use the formula(a^2-b^2)

= (x^2+4)(x^2-4)

=(x^2+4)(x^2-2^2)

=(x^2+4)(X+2)(x-2)

Hope it helps

Good luck on your assignment

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2 years ago

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lara31 [8.8K]

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2 years ago

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Tema [17]

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2 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: rational equation fraction solution algebra

7 0

2 years ago