What is the domain, range, and asymptote line of y=2^x-3
1 answer:
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Answer:
- The center (2, 2.5), radius
/ 2
Step-by-step explanation:
<u>The standard form of the equation of a circle is: </u>
- ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius
<u>Rewrite the given equation in the standard form:</u>
- 2x^2 + 2y^2 - 8x + 10y + 2 = 0
- x^2 - 4x + y^2 + 5y = -1
- x^2 - 4x + 2^2 + y^2 + 5y + (5/2)^2 = -1 + 4 + 25/4
- (x - 2)^2 + (y + 2.5)^2 = 37/4
<u>The center is:</u>
- (2, 2.5)
<u>And radius is:</u>
- <u />
