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ahrayia [7]
4 years ago
11

Solve each equation for the given variable. A=1/2bcd+bc;d

Mathematics
1 answer:
Serhud [2]4 years ago
4 0
A = \frac{1}{2}bcd + bc
2(A) = 2(\frac{1}{2}bcd + bc)
2A = 2(\frac{1}{2}bcd) + 2(bc)
2A = bcd + 2bc
2A = bc(d) + bc(2)
2A = bc(d + 2)
\frac{2A}{bc} = \frac{bc(d + 2)}{bc}
\frac{2A}{bc} = d + 2
\frac{2A}{bc} - 2 = d

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