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EleoNora [17]
3 years ago
10

Jenn and David shared a candy bar. Jenn ate three tenths. David ate four tenths. How much is left?

Mathematics
1 answer:
Masja [62]3 years ago
8 0

Answer:

\frac{3}{10} should be left in the candy bar.

Step-by-step explanation:

Jenn and David shared a candy bar. Let's assume the bar was split into 10 parts, since 10 is the denominator of the fraction.

First, we need to add how much that the candy bar was eaten so we can subtract easier.

Jenn ate three tenths.

David ate four tenths.

\frac{3}{10}+ \frac{4}{10}=\frac{7}{10}

So, seven tenths of the candy bar was eaten. We need to subtract that from a whole, because we need to know how much candy is left.

\frac{10}{10} -\frac{7}{10} = \frac{3}{10}

So, there are 3/10, or 0.3, of the candy bar left to share later.

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Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

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Answer:

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A) Look at how the negatives are compared to the others

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