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Mathematics

1 answer:

Ilya [14]3 years ago

3 0

Answer: .4

Step-by-step explanation:

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What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 4y + 4=0

Sloan [31]

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - a coordinates of the center

r - a radius

$x^2+y^2-6x+4y+4=0\ \ \ |-4\\\\x^2-2\cdot x\cdot3+y^2+2\cdot y\cdot2=-4\ \ \ |+3^2\ |+2^2\\\\\underbrace{x^2-2\cdot x\cdot3+3^2}_{(a-b)^2=a^2-2ab+b^2}+\underbrace{y^2+2\cdot y\cdot2+2^2}_{(a+b)^2=a^2+2ab+b^2}=-4+3^2+2^2\\\\(x-3)^2+(y+2)^2=3^2$

Answer:

the center: (3, -2)

the radius: 3

5 0

3 years ago

The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."

Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

$csc(\theta)=\frac{1}{sin(\theta)}$

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

6 0

3 years ago

Given f(x)2x and g(x) = x^2+3 , find f(g(x)).

MakcuM [25]

Answer:

2x^2 + 6.

Step-by-step explanation:

Replace the x in f(x) by g(x):

f(g(x)) = 2(x^2 + 3)

= 2x^2 + 6.