Answer:
They have the same x-value
f(x) has the greater minimum
Step-by-step explanation:
To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:
x = -b / 2a
Remember that a second degree equation has the following form:
ax^2 + bx + c
so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation
x = - (-8) / 2(1)
x = 8 / 2
x = 4
This means that the two functions have the same x-value.
The y value of f(x) would be
f(4) = (4)^2 - 8(4) + 7
f(4) = 16 - 32 + 7
f(4) = -9
So the vertex, or minimun value of f(x) would be at the point (4, -9).
The vertex, or minimun value of g(x) is at the point (4, -4).
So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
First we will find the value of x.
To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.
We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.
angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24
Now we can use 24 for x and find the value of angle QRO
angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67
So the answer choice B is the right answer.
Hope this helps :)<span />
Answer:
x= 20
Step-by-step explanation:
The sum of the three angles is 90 degrees
x+2x+x+10 = 90
Combine like terms
4x+10 = 90
Subtract 10
4x+10-10 = 90-10
4x= 80
Divide by 4
4x/4=80/4
x = 20
<span>C12H22O11(s)+12O2(g) =12CO2(g)+11H2O(g)</span>
Answer:
A C D is ur answer
Step-by-step explanation:
