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ohaa [14]
3 years ago
6

(Challenge question!) will give brainly

Mathematics
2 answers:
Gwar [14]3 years ago
6 0
X=y-bm is the answer you are looking for
nikklg [1K]3 years ago
6 0
Y = mx + b

y - b = mx + b - b (Subtract b from both sides this cancels out b on right side)

y - b / m = xm/m (Divide m on both sides this cancels out m on right side)

x = y - b / m (Final answer)
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2 years ago
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kati45 [8]

To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

\boxed{ \sf \: area \: of \: square =side ^{2}  }

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\rm \implies \: area = 3 ^{2}

\rm \implies9

<em>Thus, The area of 1st square is 9m²...</em>

  • The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

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\sf \: area \: of \: rectangle = length \times breadtg

\tt \dashrightarrow \: area = 10 \times 3

\tt \dashrightarrow \: area = 30m ^{2}

<em>Thus, The area of rectangle is 30m²....</em>

  • Now, Add area of all the figures to get the total area.

\bf \:total \: area = 9 + 9 + 30 \\   \bf= 48m {}^{2}

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