Answer:
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.
Step-by-step explanation:
From the boxplot Given ;
Town A :
The first quartile, Q1 = 15
Third quartile, Q3 = 30
The interquartile range, IQR = Q3 - Q1 = 30 - 15 = 15°
TOWN B :
The first quartile, Q1 = 20
Third quartile, Q3 = 40
The interquartile range, IQR = Q3 - Q1 = 40 - 20 = 20°
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.
Answer:
x = 6
Step-by-step explanation:
Triangle BCD: cos(60) = x/BC => BC = x/cos(60)
Triangle ABC: sin(45) = BC/6√2 => BC = (6√2)sin(45)
so x/cos(60) = (6√2)sin(45)
x/(1/2) = (6√2)(√2/4)
x/2 = 12/4
x = 2(3)
x = 6
Answer: D.
Step-by-step explanation:
Given : The charge of painting = $2 per square yard
Let x be the total cost of painting the triangular wall .
The base of the triangular wall = 4 yards
The height of the triangular wall = 6 yards
We know that the area of the triangle =
Thus, the area of the triangular wall =
Now, the total cost of painting the triangular wall =
Hence, the total cost of painting the triangular wall
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