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kati45 [8]
4 years ago
14

Find the slope given the y intercept and x intercept. Is the slope 11/5x like I got?

Mathematics
1 answer:
masya89 [10]4 years ago
3 0

if you are doing function c yes your slope is 11/5x


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20,10,5, ...<br> Find the 9th term.
iren [92.7K]

Answer:

0.078125.

Step-by-step explanation:

This is a geometric sequence with first term a1 = 20 and common ratio r = 10/20 = 5/10 = 0.5.

nth term = a1 r^(n -1) so here:

9th term = 20(0.5)^(9-1)

= 20(0.5)^8

= 0.078125.

6 0
2 years ago
I need some help on this question ASAP
telo118 [61]

Answer:

I would believe the answer is A

6 0
3 years ago
10^3<br> 10^14=10negative^11<br> true or false <br><br> heeellllp asap
Volgvan

Answer:

False

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)} , then

10^{3} × 10^{14} = 10^{(3+14)} = 10^{27}

8 0
3 years ago
Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.
solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is:f(x)=   \frac{9-x^2}{x^2-4}

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get f(-4)=   \frac{9-(-4)^2}{(-4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get f(-2.5)=   \frac{9-(-2.5)^2}{(-2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get f(0)=   \frac{9-(0)^2}{(0)^2-4}  = \frac{9}{-4}  = -\frac{9}{4}  < 0

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get f(2.5)=   \frac{9-(2.5)^2}{(2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get f(4)=   \frac{9-(4)^2}{(4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (3,∞)

7 0
4 years ago
Please help me with this
anastassius [24]

Answer:

(4, 5) -> (5,2)

(-3, 3) -> (-2, 0)

(-4, 5) -> (-3,2)

Step-by-step explanation:

The triangle is translated 1 unit(s) to the right and 3 unit(s) down.

3 0
3 years ago
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