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3 years ago

Write these numbers in order from least to greatest 0.65, 2/3, 3/5 , 0.5

Mathematics

1 answer:

svp [43]3 years ago

8 0

Answer:

Step-by-step explanation:

Convert the fractions to the decimals (you can use the calculator):

2/3 = 2 : 3 = 0.6666...

3/5 = 3 : 5 = 0/6

We have

0.65

0.666...

0.6

0.5

The order from least to greatest:

0.5

0.6

0.65

0.666..

$\begin{array}{c|c|c|c|c}0&.&5\\0&.&6\\0&.&6&5\\0&.&6&6&6...\end{array}$

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Of a government by whom money is paid to support services

zloy xaker [14]

Answer:

um what kinda question is this?

Step-by-step explanation:

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3 years ago

The baseball field is 9/10 of a mile from Benson’s house. Benson runs 3/10 of a mile and walks 4/10 of a mile on his way to the

inysia [295]

Answer:

2/10 I believe

Step-by-step explanation:

3/10 + 4/10= 7/10

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2 years ago

I don't know how to do this

Gre4nikov [31]

Answer:

x = -11/5 and y = 24/5

Step-by-step explanation:

Use elimination.

First, we need to multiply so that at least one variable can cancel out.

We can multiply the top equation by 2.

So we get

4x + 6y = 20

Then, we can use elimination.

The x's cancel out.

So we get 5y = 24

Or y = 24/5

Then, we can plug in this y value back into the first equation to find x.

2x + 3(24/5) = 10

2x + 72/5 = 50/5

2x = -22/5

x = -11/5

So x = -11/5 and y = 24/5

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3 years ago

The cooking club made some pies to sell at a basketball game to raise money for the new math books. The cafeteria contributed tw

Neko [114]

Answer:

Step-by-step explanation:

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3 years ago

Convert to the product of multiplication<br>a^2-b^2-4b-4

kirill [66]

$a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

<u>Step-by-step explanation:</u>

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , $a^2-b^2-4b-4$ :

⇒ $a^2-b^2-4b-4$

We know by identity that , $p^2-q^2 = (p-q)(p+q)$

⇒ $(a-b)(a+b)-4b-4$

Taking common term out as -4 :

⇒ $(a-b)(a+b)-4(b+1)$

Therefore , $a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

7 0

3 years ago