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steposvetlana [31]
3 years ago
10

Drag each label to the correct location on the chart.

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

Step-by-step explanation:

boyakko [2]3 years ago
3 0
√(-5)^2 complex
400 real
-9+10i^2 real
0+5i complex
i^8 real
√-16 complex
-2+6i complex
√10 real
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Is 2.64 greater or less than 1.9?
Schach [20]

2.64 is greater than 1.9

4 0
3 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
2 years ago
Please help!!!! I need this ASAP Help
Nutka1998 [239]

Answer:

Step-by-step explanation:

If x is -1, then the point on the parabol is (-1,4)

If x is 0, then the point on the parabol is (0,-2)

If x is 1, then the point on the parabol is (1,-6)

8 0
3 years ago
For f(x)=13^x,find f(3/2)
tekilochka [14]

Answer:

  f(3/2) = 13√13 ≈ 46.872167

Step-by-step explanation:

Put 3/2 where x is and evaluate.

  f(3/2) = 13^(3/2) = 13^(1 +1/2) = 13√13

  f(3/2) ≈ 46.872167

5 0
2 years ago
(7x-12)+(13-2x)<br><img src="https://tex.z-dn.net/?f=%287x%20-%2012%29%20%2B%20%2813%20-%202x%29" id="TexFormula1" title="(7x -
Julli [10]
The answer is : 5x+1
5 0
3 years ago
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