What is 4x squares minus 81

The table below represents a linear function in the equation represents a function. table numbers are X: -1,0,1. f(x): -3,0,3. G

Alexxx [7]

A)
SLOPE OF f(x)
To find the slope of f(x) we pick two points on the function and use the slope formula. Each point can be written (x, f(x) ) so we are given three points in the table. These are: (-1, -3) , (0,0) and (1,3). We can also refer to the points as (x,y). We call one of the points $( x_{1} , y_{1} )$ and another $( x_{2} , y_{2} )$ . It doesn't matter which two points we use, we will always get the same slope. I suggest we use (0,0) as one of the points since zeros are easy to work with.

Let's pick as follows:
$( x_{1} , y_{1} )= (0.0)$
$( x_{2} , y_{2} )= (1.3)$

The slope formula is: $m= \frac{y_{2} - y_{1} }{ x_{2}- x_{1} }$
We now substitute the values we got from the points to obtain.
$m= \frac{3-0}{ 1-0 } = \frac{3}{1}=3$

The slope of f(x) = 3

SLOPE OF g(x)
The equation of a line is y=mx+b where m is the slope and b is the y intercept. Since g(x) is given in this form, the number in front of the x is the slope and the number by itself is the y-intercept.

That is, since g(x)=7x+2 the slope is 7 and the y-intercept is 2.

The slope of g(x) = 2

B)
Y-INTERCEPT OF g(x)
From the work in part a we know the y-intercept of g(x) is 2.

Y-INTERCEPT OF f(x)
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This point will always have an x-coordinate of 0 which is why we need only identify the y-coordinate. Since you are given the point (0,0) which has an x-coordinate of 0 this must be the point where the line crosses the y-axis. Since the point also has a y-coordinate of 0, it's y-intercept is 0

So the function g(x) has the greater y-intercept

5 0

3 years ago

What is the quotient?<br> 5)50<br> O<br> A. 1<br> O B. 5<br> O C. 10<br> o D. 2

shtirl [24]

Answer:10

Step-by-step explanation: used calculator hopes this helped

4 0

3 years ago

Read 2 more answers

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=15/17and cos b=

tensa zangetsu [6.8K]

The value of $cos(a+b)$ for the angles $a$ and $b$ in standard position in the first quadrant is $-\frac{36}{85}$

We need to find the value of $cos(a+b)$ . To proceed, we need to use the compound angle formula

<h3>Cosine of a sum of two angles</h3>

The cosine of the sum of two angles $a$ and $b$ is given below

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

We are given

$sin(a)=\dfrac{15}{17}\\\\cos(b)=\dfrac{3}{5}$

We need to find $sin(b)$ and $cos(a)$ , using the identity

$sin^2(\theta)+cos^2(\theta)=1$

To find $sin(b)$ , note that

$sin^2(b)+cos^2(b)=1\\\\\implies sin(b)=\sqrt{1-cos^2(b)}$

substituting $\frac{3}{5}$ for $cos(b)$ in the identity, we get

$sin(b)=\sqrt{1-cos^2(b)}\\\\=\sqrt{1-\left(\dfrac{3}{5}\right)^2}=\dfrac{4}{5}$

To find $cos(a)$ , note that

$sin^2(a)+cos^2(a)=1\\\\\implies cos(a)=\sqrt{1-sin^2(a)}$

substituting $\frac{15}{17}$ for $sin(a)$ in the identity, we get

$cos(a)=\sqrt{1-sin^2(a)}\\\\=\sqrt{1-\left(\dfrac{15}{17}\right)^2}=\dfrac{8}{17}$

<h3>Find the value of cos(a+b)</h3>

We can now make use of the formula

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

to find $cos(a+b)$ .

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\\\\=\dfrac{8}{17}\cdot\dfrac{3}{5}-\dfrac{15}{17}\cdot\dfrac{4}{5}=-\dfrac{36}{85}$

Learn more about sine and cosine of compound angles here brainly.com/question/24305408

8 0

2 years ago

What is the equation of the line that is perpendicular to line m and passes through the point (3, 2)?

agasfer [191]

Answer:

y = $\frac{2}{5}$ x + $\frac{4}{5}$

Step-by-step explanation:

Calculate the slope of line m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 2, 2) and (x₂, y₂ ) = (0, - 3) ← 2 points on the line

m = $\frac{-3-2}{0-(-2)}$ = $\frac{-5}{0+2}$ = - $\frac{5}{2}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{5}{2} }$ = $\frac{2}{5}$ , then

y = $\frac{2}{5}$ x + c ← is the partial equation in slope- intercept form

To find c substitute (3, 2 ) into the partial equation

2 = $\frac{6}{5}$ + c ⇒ c = 2 - $\frac{6}{5}$ = $\frac{4}{5}$

y = $\frac{2}{5}$ x + $\frac{4}{5}$ ← equation of perpendicular line

7 0

2 years ago

When x=5 and y=2 (x-y)^2

GrogVix [38]

Answer:

9

Step-by-step explanation:

new formula : (5 - 2) ^2

So 5- 2 equals 3. And 3 to the second power is 9

7 0

3 years ago