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Pani-rosa [81]
3 years ago
15

Which equation correctly uses point (-2,-6) to write the equation of this line in point-slope form?

Mathematics
1 answer:
user100 [1]3 years ago
7 0

Answer is D I just took the test

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From the sum of 4x² - 2x +6 and 2x² + 4x-1, subtract 5x2 + 2x -4.
ikadub [295]

Answer:

  • x² + 9

Step-by-step explanation:

<u>Add:</u>

  • 4x² - 2x + 6 + 2x² + 4x - 1 = 6x² + 2x + 5

<u>Subtract:</u>

  • 6x² + 2x + 5 - 5x² - 2x + 4 = x² + 9
3 0
3 years ago
Read 2 more answers
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
3 years ago
What is linear expansivity?
katrin [286]
Its a type of thermal expansion and described by fractions that represents the fractional increase length of a thin beam of a material exposed to its temperature increase of one degree celcious,"
4 0
3 years ago
Please help: What is 4 1/4 divided by 3/4 equal?
Solnce55 [7]
4/3 because I typed in on my calculator
7 0
3 years ago
Which statement best describes how to determine whether f(x) = x2 – x + 8 is an even function? Determine whether –x2 – (–x) + 8
DiKsa [7]

Answer:

B.

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

9 0
3 years ago
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