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olasank [31]
3 years ago
10

The area of a rhombus is given by the formula A=1/2xy,where x and y are the lengths of the diagonals. If the diagonals of a rhom

bus have lengths 10cm and 20cm, find the area of the rhombus.
Mathematics
1 answer:
Ivahew [28]3 years ago
3 0
The area of the triangle would be 100 cm
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fred and freda share some prize money in the ratio 7:3. the prize money totaled $3000 how much does fred receive?
cupoosta [38]

Answer:

fred recives 2700 or 300 im sorry i cant help more

Step-by-step explanation:

5 0
3 years ago
In an arithmetic sequence the sum of the first six odd-numbered terms (a1,a3,a5,a7,a9 and a11) is 60. find the sum of the first
alexandr1967 [171]

Answer:

Im so sorry!

Step-by-step explanation:

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8 0
3 years ago
Triangle ABC is similar to triangle FGH.
Ivan

Answer:

i can't understand the question but if you put a link I can figure it out

8 0
3 years ago
3x + 1 = 5X-13 if anyone knows what to do can they please help ​
Elza [17]

Answer:

  x = 7

Step-by-step explanation:

First, you look at the equation. Identify the locations of variable terms (both sides of the equal sign) and the constant terms (both sides of the equal sign).

If there are any parentheses, it is a good idea to use the distributive property to eliminate them. Here, there are none.

I like to start by subtracting <em>the variable term with the smallest coefficient</em>. Here, that is 3x, so we add -3x to both sides of the equation.

  3x -3x +1 = 5x -3x -13

  1 = 2x -13 . . . . . . . . . . . . combine like terms

Now, we have the only variable term on one side of the equal sign. We want it by itself, so we need to make the -13 go away. We do that by adding its opposite to both sides of the equation:

  1 +13 = 2x -13 +13

  14 = 2x . . . . . . . . . . . . combine like terms

Finally, we want the coefficient of 2 in the x-term to disappear. We make that happen by multiplying both sides of the equation by 1/2, the reciprocal of that coefficient.

  (1/2)(14) = (1/2)(2x)

  7 = x . . . . the solution

__

It is generally a good idea to <em>check your work</em> by seeing if your solution value satisfies the equation:

  3(7) +1 = 5(7) -13 . . . . put 7 where x is in the original equation

  21 +1 = 35 -13

  22 = 22 . . . . . . x = 7 is the solution

_____

<em>Additional comment</em>

By subtracting 3x from 5x, the result is 2x with a positive coefficient. We could solve the equation just as easily by subtracting 5x from 3x. That result would be ...

  -2x +1 = -13

Subtracting 1 would give

  -2x = -14

and you would multiply by -1/2 to get x=7. I personally like to avoid having this many minus signs show up in the problem. That is why I choose to subtract the x-term with the smallest coefficient.

5 0
4 years ago
What is the equation of the line that passes through the point (-6,7) and has a slope of -5? Write the equation in slope interce
V125BC [204]

Answer:

y = -5x - 23

Step-by-step explanation:

Write it in point - slope form:

y - 7 = -5(x + 6)

rearrange:

y - 7 = -5x - 30

y = -5x - 23

8 0
3 years ago
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