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sleet_krkn [62]
3 years ago
11

Jim’s work evaluating 2(3/5)^3 is shown below.

Mathematics
2 answers:
Anni [7]3 years ago
5 0

Answer:

<em>I would say that the answer is B.</em>

<em>Step-by-step explanation:</em>

<em>took the quiz!</em>

Oksanka [162]3 years ago
4 0

Answer:

Option b.

Step-by-step explanation:

we have

2(\frac{3}{5})^{3}

Evaluate

2(\frac{3}{5})^{3}=2(\frac{3^{3}}{5^{3}})\\ \\=2(\frac{27}{125})\\ \\=\frac{54}{125}

therefore

He did not apply the power to the denominator of 3/5

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Ksivusya [100]
Let <span>simplify the equations a^7xy-a^6y-a^5x=a^4(b^4-1) and (a^mx-a^n)(a^py-a^2)=a^4b^4:
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<span>1) a^7xy-a^6y-a^5x+a^4=a^4b^4
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<span>and
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<span>2) a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4.
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<span>Equate the coefficients:
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Then n=2 \\ p=4 \\ m=3 and mnp=24.
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