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3 years ago

The sum of three numbers is 72

Mathematics

2 answers:

LekaFEV [45]3 years ago

6 0

Answer: The first number is 8

Step-by-step explanation: Let the three No. s be x, y and z respectively

given = x+ y+ z= 72

y=7x

z=7x-18

∴As we know x+ y+ z=72

i.e. x+7x+7x-18=72

15x=72+18=90

15x=90

x=90/15

∴x=8

∴y=7x

7×8=56

∴z=7x-18

56-18=38

∴The first no. is x=8

The second no. is y=7x = 56

The third no. is z=7x-18 = 38

Lena [83]3 years ago

4 0

Answer:

Let the first number be x, second number be 7x and the third number be 7x-18. Then,

Sum of the numbers=72

or, x+(7x) +(7x-18)=72

or, 15x=90

or, x=6

So, the first number is 6.

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3 years ago

In two or more complete sentences, describe how to use technology to construct an appropriate regression model for the given dat

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2 years ago

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

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3 years ago

(4x+2y-6z) + (5y-2z+7x) + (-9z-2x-3y)

Free_Kalibri [48]

Answer:

9x+4y-17z

Step-by-step explanation:

first open brackets with d signs

dat is= 4x+2y-6z+5y-2z+7x-9z-2x-3y

collect like terms and = 4x+7x-2x+2y+5y-3y-6z-2z-9z= 9x+4y-17z

7 0

4 years ago