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slamgirl [31]
3 years ago
12

If the scale factor of Figure A to Figure B is 7:2, find the perimeter of Figure A.

Mathematics
2 answers:
Nataly [62]3 years ago
8 0
I kno 2:7 I believe on a coordinate grid ur talkin about right then I’m right
Daniel [21]3 years ago
6 0

Answer:

  • I honestly don't k ow wish i can help if you can help me with one
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CAN SOMEONE HELP ME WITH THIS PLZ! <3
coldgirl [10]

Answer:

D. A = πr^2

Step-by-step explanation:

The formula of the area of a circle is <u>A = πr^2</u>.

6 0
2 years ago
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Linda buys a packet of biscuits, there were p biscuits in it. She eats y of them and gave the rest to her friend. How many biscu
Mkey [24]
She eats y out of the p
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3 years ago
Simply the following question in the photo
grin007 [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
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List the transformations of the function<br> j(x) = 3(-7(x+2))-4
allsm [11]

Answer:

transformations of function 3(-7(x+2))-4

  • vertical stretch
  • horizontal compression
  • translates left
  • translates down
  • reflection across y-axis
8 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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