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3 years ago

If the scale factor of Figure A to Figure B is 7:2, find the perimeter of Figure A.

Mathematics

2 answers:

Nataly [62]3 years ago

8 0

I kno 2:7 I believe on a coordinate grid ur talkin about right then I’m right

Daniel [21]3 years ago

6 0

Answer:

I honestly don't k ow wish i can help if you can help me with one

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CAN SOMEONE HELP ME WITH THIS PLZ! <3

coldgirl [10]

Answer:

D. A = πr^2

Step-by-step explanation:

The formula of the area of a circle is A = πr^2.

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2 years ago

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Linda buys a packet of biscuits, there were p biscuits in it. She eats y of them and gave the rest to her friend. How many biscu

Mkey [24]

She eats y out of the p

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3 years ago

Simply the following question in the photo

grin007 [14]

Answer:

Step-by-step explanation:

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3 years ago

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List the transformations of the function j(x) = 3(-7(x+2))-4

allsm [11]

Answer:

transformations of function 3(-7(x+2))-4

vertical stretch
horizontal compression
translates left
translates down
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3 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

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3 years ago