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Akimi4 [234]
4 years ago
8

Which box plot has the most variability A,B,C,D

Mathematics
1 answer:
tamaranim1 [39]4 years ago
3 0
IM LITERALLY BALLING MY EYES OUT
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What is the missing coefficient?
Afina-wow [57]

For this case we have the following expression:

(15x ^ 2 + 11y ^ 2 + 8x) - (7x ^ 2 + 5y ^ 2 + 2x) =

We eliminate the parentheses taking into account that:

- * + = -\\15x ^ 2 + 11y ^ 2 + 8x-7x ^ 2-5y ^ 2-2x

We add similar terms:

15x ^ 2-7x ^ 2 + 11y ^ 2-5y ^ 2 + 8x-2x =

Different signs are subtracted and the sign of the major is placed:

8x ^ 2 + 6y ^ 2 + 6x

Finally, the expression is reduced to:

8x ^ 2 + 6y ^ 2 + 6x

Answer:

8x ^ 2 + 6y ^ 2 + 6x

Option B

6 0
3 years ago
Read 2 more answers
PLEASE HELP GEOMOTRY
Rom4ik [11]

Answer:

The first one doesn't help while both the second and third helps in finding the vertices

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
For f(x) = 3x - 5 and g(x) = x^2 + 2 find (f+ g)(x).
SpyIntel [72]

Answer:

777

Step-by-step explanation:kkk

888u

3 0
4 years ago
Clare
Luden [163]
7 1/2 miles per hour

(43 1/8) / (5 3/4) = 7 1/2
4 0
4 years ago
The as x approaches 0 of tan^2x/x
uysha [10]

L=Lim tan(x)^2/x x->0

Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.

d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)

d(x)/dx = 1

=>

L=2tan(x)sec^2(x)/1 x->0

= (2(0)/1^2)/1

=0/1

=0


Another way using series,

We know that tan(x) = x+x^3/3+2x^5/15+.....

then tan^2(x), using binomial expansion gives

x^2+2*x^4/3+.... (we only need two terms)

and again apply l'Hôpital's rule, we have

L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1

=0 as x->0

3 0
3 years ago
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