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3 years ago

15

A month subscription to a website costs $10 to join and $15.50 per month. Write an equation in slope-intercept form to represent

the cost. Identify your variables and what they represent.

1 answer:

just olya [345]3 years ago

3 0

Answer:

y = $15.50x + $10

Step-by-step explanation:

y =mx +b

y = $15.50x + $10

m = cost per months

x= number of months

b = Money to join

y= total cost

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Tom goes on hoilday south africa

Evgen [1.6K]

Answer:

Yes, good for him. lol

Step-by-step explanation:

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3 years ago

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Find the missing measurement for each quadrilateral 5) this is rhombus ABCD

a_sh-v [17]

To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of a rhombus are all congruent (the same length.) Opposite angles of a rhombus are congruent (the same size and measure.)

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3 years ago

What are the side lengths of a 45-45-90 triangle with a hypotenuse of 10root2?

scoundrel [369]

Answer:

10

Step-by-step explanation:

let the lengths of sides=x (each)

x²+x²=(10√2)²

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3 years ago

The perimeter, P, of a rectangle is equal to twice the sum of the length and width of the rectangle. Determine the width of a re

svetoff [14.1K]

Answer:

12 inches

Step-by-step explanation:

5 + 5 = 10

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3 years ago

If the probability of surviving a head on car accident at 55 mph is 0.097, then what is the probability of not surviving

BabaBlast [244]

The probability of not surviving a head-on car accident is: 0.903

Step-by-step explanation:

The probabilities of occurrence and non-occurrence of an event add up to one.

If p is the probability that an even will happen and q is the probability that it will not happen

Then

$p+q=1$

Here,

Probability of surviving = p = 0.097

Probability of not surviving = q = ?

$0.097 + q = 1\\q = 1 - 0.097\\q = 0.903$

The probability of not surviving a head-on car accident is: 0.903

Keywords: Probability, Inverse

Learn more about probability at:

#LearnwithBrainly

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3 years ago