Question

One length of a rectangular garden lies along a patio wall.​ However, the rest of the garden is enclosed by 28 feet of fencing. If the length of the garden is twice its​ width, what is the area of the​ garden?

Answer 1

Answer:

The area of rectangle is 98 ft.sq.

Step-by-step explanation:

We are given one length of a rectangular garden lies along a patio wall.​

Let the width of garden be x

Length of garden = Twice its​ width=2x

Length garden enclosed by fencing =l+2b=2x+2x= 4x

We are given that the rest of the garden is enclosed by 28 feet of fencing.

So,4x=28

x=7

Width of garden = 7 feet

length of garden = 2x=2(7)=14 feet

Area of garden = $Length \times Breadth = 7 \times 14=98 ft^2$

Hence The area of rectangle is 98 ft.sq.