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Furkat [3]
3 years ago
14

Devon purchased a new car valued at $16,000 that depreciated continuously at a rate of 35%. Its current value is $2,000. The equ

ation 2,000 = 16,000(1-r) t represents the situation, where t is the age of the car in years and r is the rate of depreciation. About how old is Devon’s car? Use a calculator and round your answer to the nearest whole number.
Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

Step-by-step explanation:

Use the equation 2,000 = 16,000(1-r)^t to solve for t;

2000 = 16000(1-0.35)^t

Divide both sides by 16000

2000/16000 = 0.65^t

0.125 =0.65^t

Introduce logarithm on both sides;

<em>ln</em> 0.125 = t <em>ln</em> 0.65

Divide both sides by <em>ln</em> 0.65;

(<em>ln</em> 0.125) / (<em>ln</em> 0.65) = t

-2.07944/ -0.4308 = t

4.827 = t

t= 5 (as a whole number)

Therefore, the car is about 5 years old.

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lesya [120]
Difference is subtract so 400-148=252
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3 years ago
HELP ME WITH MATH HOMEWORK please 11points㋛㋛
Korvikt [17]

Answer:

7. Option B:40 is the correct answer.

8. Option D: y = 40x+75 is the correct answer.

Step-by-step explanation:

Given that:

Charges per hour = $40

Fee charged by repairman = $75

x = number of hours

y = total fee

According to given statement;

y = 40x+75

The standard equation is

y = mx + b

On comparing;

Slope of the line is given by m, therefore

Slope = m = 40

Hence,

7. Option B:40 is the correct answer.

8. Option D: y = 40x+75 is the correct answer.

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3 years ago
HURRY BRAINLIEST. <br>Write the relation as a set of ordered pairs. ​
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Answer:

B

Step-by-step explanation:

8 0
3 years ago
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

\frac{d(u\cdot v)}{dx}=u'v+uv'

Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

3 0
3 years ago
1) Write an equation that includes a variable to show how much money matt started with
12345 [234]
1) m-13=7

2)m-13=7
m-13+13=7+13
m=20
so he had $20 he spent $13 so $7 was left!


BRAINLIEST???
7 0
3 years ago
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