Question

What is the volume of the cube shown?

Answer 1

Answer: $11\frac{25}{64}in^3$

Step-by-step explanation:

$V=a^3$

This is your mixed number. $2\frac{1}{4}in$

Start by converting the mixed number to an improper fraction. To do this, you take the big number, multiply it by the denominator, add the numerator; and all of this over the same denominator.

$\frac{2*4+1}{4}in=\frac{8+1}{4}in=\frac{9}{4}in$

Now plug this into the formula:

$V=(\frac{9}{4}in)^3$

As you should remember;

$(\frac{x}{y})^n=\frac{x^n}{y^n}$

------------------------------------------------------------

$V=\frac{9^3}{4^3}in^3$

Solve;

$V=\frac{729}{64}in^3$

Now convert to mixed number by dividing.

729/64=11

64

------

 8'9

  64

  -------

    25

11 is the big number, 25 the numerator and 64 the denominator.

$11\frac{25}{64}$

Answer 2

The answer is the last one.